InterviewSolution
Saved Bookmarks
| 1. |
Consider the parabola (x−1)2+(y−2)2=(12x−5y+3)2169Column IColumn IIa. Locus of point of intersection of perpendicular tangent p. (12x−5y−2=0) b. Locus of foot of perpendicular from focus upon any tangent q. (5x+12y−29=0)c. Line along which minimum length of focal chord occurs r. (12x−5y+3=0) d. Line about which parabola is symmetrical s. (24x−10y+1=0) |
|
Answer» Consider the parabola (x−1)2+(y−2)2=(12x−5y+3)2169 |
|