1.

Consider the reaction 4 NO_(2)(g) +O_(2)(g)rarr 2N_(2)O_(5)(g), Delta_(r)H = - 111 kJ . If N_(2)O_(5)(s) is formed instead ofN_(2)O_(5)(g) in the above reaction, the Delta_(r)H value will be ( given , DeltaHof sublimation for N_92)O_(5) is 54kJ mol^(-1))

Answer»

`- 165kJ`
`+54 kJ`
`+219 kJ`
` -219 kJ`

SOLUTION :
By HESS's LAW,`DELTAH+ 54 = - 111kJ` or `DeltaH= - 165kJ`


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