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Consider the reaction, N_(2)(g)+3H_(2)(g) hArr 2NH_(3)(g) . Explain the effect of pressure on this equilibrium reaction. |
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Answer» Solution :`N_(2)(g) + 3H_(2)(g) HARR 2NH_(3)(g)` In the above equlibirum, if the pressure is increased, the volume will decrease, The system responds to this effect by reducing the number of gas molecules , i.e, It favours the FORMATION of ammonia. If the pressure is reduced, the volume will increase. It favours the decomposition of ammonia. |
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