Consider the reaction where K_(p) = 0*497 "at 500 K PCl_(5) (g) hArr PCl_(3) (g) + Cl_(2) (g)If the three gases are mixed in a rigid container so that the partial pressure of each gas is initially1 atm, which is true ?

Consider the reaction where K_(p) = 0*497 "at 500 K PCl_(5) (g) hArr

1.	Consider the reaction where K_(p) = 0*497 "at 500 K PCl_(5) (g) hArr PCl_(3) (g) + Cl_(2) (g)If the three gases are mixed in a rigid container so that the partial pressure of each gas is initially1 atm, which is true ?
Answer» More `PCl_(5)` will be PRODUCED More `PCl_(3)` will be produced Equilibrium will be established when 50% of the REACTION is complete None of the above Solution :`Q_(p) = (p_(PCl_(3))xxp_(Cl_(2)))/(p_(PCl_(5)))=(1 atm xx1 atm )/(1atm )=1` As `Q_(p) gt K_(c)` , equilibrium will go in the BACKWARD direction , i.e., more `PCl_(5)` will be produced .