Consider the reactions : 2S_(2)O_(3(aq))^(2-)+I_(2(s))toS_(4)O_(6(aq))^(2-)+2I_((aq))^(-) 2S_(2)O_(3(aq))^(2-)+2Br_(2(l))+5H_(2)O_((l))to2SO_(4(aq))^(2-)+4Br_((aq))^(-)+10H_((aq))^(+)

Consider the reactions : 2S_(2)O_(3(aq))^(2-)+I_(2(s))toS_(4)O_(6(aq)

1.	Consider the reactions : 2S_(2)O_(3(aq))^(2-)+I_(2(s))toS_(4)O_(6(aq))^(2-)+2I_((aq))^(-) 2S_(2)O_(3(aq))^(2-)+2Br_(2(l))+5H_(2)O_((l))to2SO_(4(aq))^(2-)+4Br_((aq))^(-)+10H_((aq))^(+)
Answer» Solution :In `S_(2)O_(3)^(-2)`, OXIDATION number of S is +2. Where in `S_(4)O_(6)^(-2)` is +2.5. In `SO_(4)^(-2)`, oxidation number of S is +6. `Br_(2)` is STRONG oxidising agent than `I_(2)`. So `Br_(2)` is convert `S_(2)O_(3)^(-2)` into `SO_(4)^(-2)`. In which oxidation number of oxygen is `S_(2)O_(3)^(-2)` is (+2) and `SO_(4)^(-2)` is (+6). So, it is oxidise (+2) into (+6). While `I_(2)` is weak oxidizing agent. Therefore, it oxidised `SO_(3)^(-2)` (S = +2) to `S_(4)O_(6)^(-2)` (S = +2.5). Therefore, it gives different reactions.