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Consider the reactions : (a) 6CO_2(g) +6H_2O(l) rarr C_6H_(12)O_6(aq) +6O_2(g) (b) O_s(g) +H_2O_2(l) rarr H_2O(l) +2O_2(g) Why it is more appropriate to write these reactions as : (a) 6CO_2(g) +12H_2O(l) rarr C_6H_(12)O_(6)(aq)+6H_2O(l)+6O_2(g) (b) O_3 (g) +H_2O_2(l) rarr H_2O(l)+O_2(g)+O_2(g) Also suggest a technique to investigate the path of the above (a) and (b) redox reactions . |
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Answer» Solution :It is believed that the PHOTOSYNTHESIS reaction occurs. In two steps . In the first step , `H_2O` decomposes to give `H_2 and O_2` in the pressure of CHLOROPHYLL and the `H_2` produced reduces `CO_2 " to " C_6H_(12)O_6` in the second step , During the second step , some `H_2O` molecules are also produced and therefore , the reaction occurs as : `{:("(i)"12H_(2)O(l)rarr12H_(2)(g)+6O_(2)(g)),("(II)"6CO_(2)(g)+12H_(2)(g)rarrC_(6)H_(12)O_(6)(s)+6H_(2)O(l)),(bar("(iii) "6CO_(2)(g)+12H_(2)O(l)rarrC_(6)H_(12)O_(6)(s)+6H_(2)O(l)+6O_(2)(g)"")):}` Therefore , it is more appropriate to write the reaction for photosynthesis as (iii) because it MEANS that 12 moleules of `H_2O` are used per molecule of carhydrate and `6H_2O` molecules are produced per molecule of carbohydrate during the PROCESS. (ii) `O_2` is written two times in the product which suggests that `O_2` is being obtained from the two reactants as `{:(""O_3(g) rarrO_2(g)+O(g)),(H_2O_2(l)+O(g)rarrH_2O(l)+O_2(g)),(bar((O_3)(g)+H_2O_2(l)rarrH_2O(l)+O_2(g)+O_2(g))):}` The path of the reaction can be studies by using `H_2O^(16)` in reaction (a) or by using `H_2O_2^(18) " or" O_3^(18)` in reaction (b). |
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