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Consider the simplest alkane having only one `2^@C` one `3^@C`, and one `4^@C`, how may structural isomers are possible?A. only oneB. ThreeC. TwoD. four |
Answer» Correct Answer - B The three kinds of C atoms `[H-underset(|)overset(|)(C)-H,-underset(|)overset(|)(C)-H`, and `underset(|)overset(|)(C)-]` can be joined in three different ways, (i). `2^(@),3^(@),4^(@)` (ii). `2^(@),4^(@),3^(@)` (iii). `4^(@)-2^(@)-3^(@)` `Me-underset(H)underset(|)overset(H)overset(|)(C)-underset(H)underset(|)overset(Me)overset(|)(C)-underset(Me)underset(|)overset(Me)overset(|)(C)-Me" "Me-underset(H)underset(|)overset(H)overset(|)(C)-underset(Me)underset(|)overset(Me)overset(|)(C)-underset(H)underset(|)overset(Me)overset(|)(C)-Me` `Me-underset(Me)underset(|)overset(Me)overset(|)(C)-underset(H)underset(|)overset(H)overset(|)(C)-underset(H)underset(|)overset(Me)overset(|)(C)-Me` Here e, stands for methyl, that the reverse orde3r `3^(@)-2^(@)-4^(@)` gives the same isomer. |
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