Consider the situation as shown in the diagram. The pulley has radius `R` and moment of inertia `I`. The block is release when the spring (spring constant `k`) is unstretched. Find the speed of block when the vlock has fallen a distance `h`. Assume no slipping.

Consider the situation as shown in the diagram. The pulley has radius

1.	Consider the situation as shown in the diagram. The pulley has radius `R` and moment of inertia `I`. The block is release when the spring (spring constant `k`) is unstretched. Find the speed of block when the vlock has fallen a distance `h`. Assume no slipping.
Answer» Decrease in the gravitation potential energy of block `=` gain in the kinetic energy of (block `+` pulley) `+` spring energy `mgh=(1)/(2)mv^(2)+(1)/(2)Iomega^(2)+(1)/(2)kh^(2)` `omega=(v)/(R )` `mgh-(1)/(2)kh^(2)=(1)/(2)mv^(2)+(1)/(2)I((v)/(R))^(2)` `=(1)/(2)mv^(2)(1+(I)/(mR^(2)))` `v=sqrt((2mgh-kh^(2))/(m(1+(I)/(mR^(2)))))`

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Consider the situation as shown in the diagram. The pulley has radius `R` and moment of inertia `I`. The block is release when the spring (spring constant `k`) is unstretched. Find the speed of block when the vlock has fallen a distance `h`. Assume no slipping.

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