InterviewSolution
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InterviewSolution
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Consider the situation shown in fig. The two slits `S_(1)` and `S_(2)` placed symmetrically around the central line are illuminated by monochromatic light of wavelength `lambda`. The separation between the slit is d. The ligth transmitted by the slits falls on a screen `S_(0)` placed at a distance D form the slits. The slit `S_(3)` is at the central line and the slit `S_(4)` is at a distance z from `S_(3)` Another screen `S_(c)` is placed a further distance D away from `S_(c)` Find the ratio of the maximum to minimum intensity observed on `S_(c)` If `z = (lambda D)/(4 d)`A. `[3 - 2 sqrt 2]^(2)`B. `[3 + sqrt 2]^(2)`C. `[3 - sqrt 2]^(2)`D. `[3 + 2 sqrt 2]^(2)` |
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Answer» Correct Answer - d `z = (lambda D)/(4d)` `Delta x = y (d)/(D) = (lambda D)/(4 d) (d)/(D) = (lambda)/(4)` `phi = (2 pi)/(lambda) ((lambda)/(4)) = (pi)/(4)` Intensity at `S_(4): I_(4) = 2 I_(0) (1 + cos ((pi)/(2))) = 2 I_(0)` Intensity at `S_(3): I_(3) = 4 I_(0)` `:. (I_(max))/(I_(min))=([(4I_(0))^(1//2)+(2I_(0))^(1//2)]^(2))/([(4I_(0))^(1//2)-(2I_(0))^(1//2)]^(2))=[((2+sqrt(2)))/((2-sqrt(2)))]^(2)` `= [((2 + sqrt 2)^(2))/(4 - 2)]^(2) = (1)/(4) [4 + 2 + 4 sqrt 2]^(2)` `= (1)/(4) [ 6 + 4 sqrt 2]^(2) = [3 + 2 sqrt 2]^(2)` |
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