InterviewSolution
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InterviewSolution
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Consider the situation shown in fig. The two slits `S_(1)` and `S_(2)` placed symmetrically around the central line are illuminated by monochromatic light of wavelength `lambda`. The separation between the slit is d. The ligth transmitted by the slits falls on a screen `S_(0)` placed at a distance D form the slits. The slit `S_(3)` is at the central line and the slit `S_(4)` is at a distance z from `S_(3)` Another screen `S_(c)` is placed a further distance D away from `S_(c)` Find the ratio of the maximum to minimum intensity observed on `S_(c)` If `z = (lambda D)/(d)`A. 4B. 2C. `oo`D. 1 |
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Answer» Correct Answer - c `z = (lambda d)/(d)` `Delta x` at `S_(4): Delta x = (lambda D)/(d) (d)/(D) = lambda` Hence, maxima at `S_(4)` as well as `S_(3)` Resultant intensity at `S_(4). I = 4 I_(0)` `:. (I_(max))/(I_(min)) = ([(4 I_(0))^(1//2) + (4 I_(0))^(1//2)]^(2))/([(4 I_(0))^(1//2) - (4 I_(0))^(1//2)]^(2) )= oo` |
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