InterviewSolution
Saved Bookmarks
| 1. |
Consider the situation shown in figure. The plates of the capacitor have plate area `1A = lb1` and are clamped in the laboratory. The dielectric slab is released from rest with length a inside the capacitor. Neglecting any effect of friction or gravity, show that the slab will execute periodic motion and find its time period. |
|
Answer» Correct Answer - `8xxsqrt((Md(l-a))/(bepsilon_(0)(K-1)V^(2)))` |
|