Consider the system of weights P_(1)=1 kg,P_(2) = 2 kg,P_(3) = 5kg and P_(4) = 0.5 kg as shown in Figure 7.14. alpha = 30^(@), g = 9.8 ms^(-2) and the coefficient of friction between the weights and the planes is 0.2 Find (a) the acceleration of the system (b) tensions in the strings between P_(1) and P_(2) and that between P_(2) and P_(2) respectively and (c) the force with which P_(4) presses down on P_(3) [Hint : Make free-body diagrams and apply Newton's law of motion after resolving the forces acting on a body along and perpendicular to the plane on which it lies]

Consider the system of weights P_(1)=1 kg,P_(2) = 2 kg,P_(3) = 5kg and

1.	Consider the system of weights P_(1)=1 kg,P_(2) = 2 kg,P_(3) = 5kg and P_(4) = 0.5 kg as shown in Figure 7.14. alpha = 30^(@), g = 9.8 ms^(-2) and the coefficient of friction between the weights and the planes is 0.2 Find (a) the acceleration of the system (b) tensions in the strings between P_(1) and P_(2) and that between P_(2) and P_(2) respectively and (c) the force with which P_(4) presses down on P_(3) [Hint : Make free-body diagrams and apply Newton's law of motion after resolving the forces acting on a body along and perpendicular to the plane on which it lies]
Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`6.87 <a href="https://interviewquestions.tuteehub.com/tag/ms-549331" style="font-weight:bold;" target="_blank" title="Click to know more about MS">MS</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)` (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) `8.83 N,16.12 N` (<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>) 1.465 N</body></html>