Consider the usual algorithm for determining whether a sequence of parentheses is balanced. The maximum number of parentheses that appear on the stack AT ANY ONE TIME when the algorithm analyzes: (()(())(()))?(a) 1(b) 2(c) 3(d) 4 or moreIt is really nice to ask questions here. Thank you

Consider the usual algorithm for determining whether a sequence of par

1.	Consider the usual algorithm for determining whether a sequence of parentheses is balanced. The maximum number of parentheses that appear on the stack AT ANY ONE TIME when the algorithm analyzes: (()(())(()))?(a) 1(b) 2(c) 3(d) 4 or moreIt is really nice to ask questions here. Thank you
Answer» The correct answer is (c) 3 Easiest explanation - In the entire parenthesis BALANCING method when the incoming token is a left parenthesis it is PUSHED into stack. A right parenthesis makes pop operation to delete the elements in stack till we get left parenthesis as top most element. 3 elements are there in stack before right PARENTHESES comes. THEREFORE, MAXIMUM number of elements in stack at run time is 3.

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Consider the usual algorithm for determining whether a sequence of parentheses is balanced. The maximum number of parentheses that appear on the stack AT ANY ONE TIME when the algorithm analyzes: (()(())(()))?(a) 1(b) 2(c) 3(d) 4 or moreIt is really nice to ask questions here. Thank you

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