1.

Consider thecompounds, BCl_(3) and "CCl"_(4). How will they behave with water ? Justify .

Answer»

Solution :The B atom in `BCl_(3)` has only six electronsin the valence shell and hence isan electron-deficientmolecule. It easily acceptsa pair of electrons donated by waterand hence `BCl_(3)`undergoeshydrolysis to form boric acid`(H_(3)BO_(3))` and HCl.
`BCl_(3) rarr + 3H_(2)O rarr H_(3)BO_(3) + 3HCl`
In contrast,C atom is`"CCl"_(4)` has 8 electrons in the valenceshell.Therefore, it isan electron-precisemolecule and henceneither accepts nor donates a pair ofelectrons. In other words , it does not accept apair of electronsfrom `H_(2)O`molecule and hence `"CCl"_(4)` does not under go HYDROLYSIS in WATER.


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