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Answer» `RS^(Θ)` is less basic and less nucleophilic than `RO^(Θ)` `RS^(Θ)` is less basic but more nucleophilic than `RO^(Θ)` `RS^(Θ)` is more basic and more nucleophilic than `RO^(Θ)` `RS^(Θ)` is more basic but less nucleophilic than `RO^(Θ)` Solution :Since O-H BOND is stronger than S-H bond, therefore, `RO^(-)` has a GREATER TENDENCY to ACCEPT a proton than `RS^(-)` and hence `RO^(-)` is a stronger base than `RS^(-)`. Conversely, since S is less electro-negative than O, therefore, `RS^(-)` is more willing to donate a pair of ELECTRONS than `RO^(-)` and hence `RS^(-)` is more nucleophilic than `RO^(-)`. Thus, option (b) is correct.
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