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Consider three boxes, each containing 10balls labelled 1, 2, ...., 10. Suppose one ball is randomly drawn from each of the boxes. Denote by n1, the label of the ball drawn from the ith box, (i = 1, 2, 3). Then, the number of ways in which the balls can be chosen such that n1 < n2 < n3 is : (1) 82 (2) 240 (3) 120 (4) 164 |
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Answer» The correct option (3) 120 Explanation: Total number of ways = 10C3 = (10.9.8)/6 = 120 |
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