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Consider three flasks in diagram below. Assuming that connecting tube has negligible volume and all three falsks are at same temperature. If only 1 and 2 stopcocks are opened then select correct option(s).A. `P_(HCl)=(1)/(2)` atmB. `P_(NH_(3))=0` atmC. `P_(NH_(3))+P_(HCl)=(1)/(2)` atmD. `P_(He)=5` atm |
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Answer» `n_(HCl)=(PV)/(RT)=(2xx1)/(RT)` `n_(NH_(3))=(PV)/(RT)=(1xx1)/(RT)` `NH_(3)+HClrarrNH_(4)Cl(s)` moles `(1)/(RT) (2)/(RT)` `0 (1)/(RT)` `n_(HCl)` remain after reaction =`(1)/(RT)` For `HCl(g):-P_("new")(V+V)=nRT` `P_("new")xx2=(1)/(RT)xxRT` `(P_(HCl))_("final")=P_("new")=(1)/(2)atm=P_("total")` `P_(NH_(3))=0(LR)` |
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