1.

Consider two organ pipes of same length in which are organ is closed and another organ pipe is open. If the fundamental frequency of closed pipe is 250 Hz. Calculate the fundamental frquency of the open pipe.

Answer»

Solution :FUNDAMENTAL frequency of closed organ pipe
`f_(c) = (V)/(4l) = 250 Hz`
Fundamental frequency of open organ pipe `f_(o) = (v)/(2l) = ?`
`(f_(c))/(f_(o)) = (v)/(4l) xx (2l)/(v) = (1)/(2)`
`f_(o) = 2f_(c) = 2 xx 250`
`f_(o) = 500` Hz


Discussion

No Comment Found