Consider two sound waves with wavelengths 5 m and 6 m . If these two waves propagate in a gas with velocity 330 ms^(-1) . Calculate the number of beats per second .

Consider two sound waves with wavelengths 5 m and 6 m . If these two w

1.	Consider two sound waves with wavelengths 5 m and 6 m . If these two waves propagate in a gas with velocity 330 ms^(-1) . Calculate the number of beats per second .
Answer» SOLUTION :Given `lambda_(1) = 5m` and `lambda_(2) = 6` m Velocity of sound waves in a gasis v = `330 MS^(-1)` The relation between wavelength and velocity is `v = lambda F implies f = (v)/(lambda)` The frequency corresponding to wavelength `lambda_(1)` is `f_(1) = (v)/(lambda_(1)) = (330)/(5) = 66` Hz The frequency corresponding to wavelength `lambda_(1)` is `f_(2) = (v)/(lambda_(2))= (330)/(6) = 55` Hz The number of beats per second is `\|f_(1) - f_(2) \| = \|66- 55\| = 11` beats per sec