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Consider two springs whose force constants are 1Nm^(-1) and 2N m^(-1) which are connected in series. Calculate the effective spring constant (k_(s)) and comment on k_(s). |
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Answer» Solution :`k_(1)=1NM^(-1),k_(2)=2Nm^(-1)` `k_(s)=(k_(1)k_(2))/(k_(1)+k_(2))Nm^(-1)` `k_(s)=(1xx2)/(1+2)=(2)/(3)Nm^(-1)` `k_(s)ltk_(1)andk_(s)ltk_(2)` Therefore, the EFFECTIVE spring constant is LESSER than both `k_(1) and k_(2)`. |
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