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Consider two springs with force constants 1 Nm^(-1) and 2Nm^(-1) connected in parallel. Calculate the effective spring constant (k_(p)) and comment on k_(p). |
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Answer» Solution :` k_1 = 1 NM^(-1) , k_2 = 2Nm^(-1)` ` k_p = k_1 + k_2 + Nm^(-1)` `k_p = 1 + 2=3 Nm^(-1)` ` k_p gt k_1 " and " k_p gt k_2` Therefore, the EFFECTIVE spring constant is greater than both `k_1 " and " k_2` |
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