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Considering four sub-intervals, the value of int_(0)^(1)(1)/(1+x)dx by Trapezoidal rule,is |
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Answer» `0.6870` ` Tapezoidal rule givee `int _(0)^(1)(1)/(1+x) dx=(h)/(2)[ y_(0)+2(y_(1)+y_(2)+y_(3))+y_(4)]` `=(1-0)/(2xx4)[1+2(0.8+0.67+0.571)+0.5]` `=0.6977` |
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