Considering `H_2O` as a weak field ligand, the number of unpaired electrons in `[Mn(H_2O)_6]^(2+)` will be (At. no. of `Mn=25`)A. (a) twoB. (b) fourC. (c) threeD. (d) five

Considering `H_2O` as a weak field ligand, the number of unpaired elec

1.	Considering `H_2O` as a weak field ligand, the number of unpaired electrons in `[Mn(H_2O)_6]^(2+)` will be (At. no. of `Mn=25`)A. (a) twoB. (b) fourC. (c) threeD. (d) five
Answer» Correct Answer - D `Mn^(25)rarr3d^5+4s^2` ` Mn^(2+) to 3d^(6) In presence of weak ligand field, there will be no pairing of electrons. So it will form a high spin complex. i.e. the number of unpaired electrons `=5`.

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Considering `H_2O` as a weak field ligand, the number of unpaired electrons in `[Mn(H_2O)_6]^(2+)` will be (At. no. of `Mn=25`)A. (a) twoB. (b) fourC. (c) threeD. (d) five

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