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Considering normal incident of ray, find equivalent refractive index of combination of two slabs shown in figure. A. `1.8`B. `1.43`C. 2D. none of these |
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Answer» (b) The equivalent refractive index of combination of slab for normal incidence is `mu=(Sigma t_(l))/(Sigma (t_(l))/(mu_(l)))` In this case` mu=(t_(1)+t_(2))/((t_(1))/(mu_(1))+(t_(2))/(mu_(2)))=(10+15)/(10/(4/3)+15/(3/2))` `=25/(7.5+10)=25/(17.5=1.43` |
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