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InterviewSolution
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Considering the parameters such as bond dissociation enthalpy, electron gain enthalpy and hydration enthalpy compare the oxidising power of F2 and Cl2. |
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Answer» The electrode potential of F2 (+ 2.87V) is much higher than that of Cl2 (+ 1.36V) therefore, F2 is a much stronger oxidising agent than Cl2. This can be explained as under: Electrode potential depends upon three factors: 1. bond dissociation enthalpy 2. electron gain enthalpy 3. hydration enthaply. Although electron gain enthalpy of fluorine is less negative (-333 kJ mol-1) than that of chlorine (-349 kJ mol-1) the bond dissociation enthalpy of F – F bond is much lower (158.8 kJ mol-1) than that of Cl – Cl bond (246.6 kJ mol-1) and hydration enthalpy of F– ion (515kJ mol-1) is much higher than that of Cl–ion (381 kJ mol-1). The last two factors are more that compensate the less negative electron gain enthalpy of F2. As a result, electrode potential of F2 is higher than that of Cl2 and hence F2 is a much stronger oxidising agent than Cl2. |
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