InterviewSolution
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InterviewSolution
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Constant as eliptical rail `PQ` in the varticle plain with `OP = = 3m ` and `OQ= 4 m` . A block of mass `1` kg is pailed along the rail from `P` to `Q` with a force of `18 N` , which is always parallel to less `PQ` Assuming are frictionless losess , the kinetic energy the block when `0` reches `Q` is `( nxx 10)` pales . THe velie of a (Take acceleration due to gravity ) `= 10ms^(-2))` |
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Answer» work done = increase in potential energy +gain in kinetic energy `F xx d = mgh + gain in K. E. ` `18 xx 5 = 1 xx 10 xx 4 + gin in K. E. ` `:. Gain in K.E. = 50 J =10 n` `:. N = 5 ` . |
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