InterviewSolution
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Constant current of `1` a flows along three branches of wire frame as shown. The frame is a combination of two equilateral triangles `ACD` and `CDE` of side `1 m`. It is place in uniform magnetic field `B=4 T` acting perpendicular to the plane of paper. The magnitude of magnitude force acting on the frame is A. `12 N`B. `24 N`C. `36 N`D. zero |
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Answer» Correct Answer - A Since `vecF_(AD)=vecF_(CD)=vecF_(CED)` Hence net force on frame `= 3vecF_(CD)` `=3i(vecixxvecb)=3xx1xx1xx4` `F=12 N` |
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