1.

Constant current of `1` a flows along three branches of wire frame as shown. The frame is a combination of two equilateral triangles `ACD` and `CDE` of side `1 m`. It is place in uniform magnetic field `B=4 T` acting perpendicular to the plane of paper. The magnitude of magnitude force acting on the frame is A. `12 N`B. `24 N`C. `36 N`D. zero

Answer» Correct Answer - A
Since `vecF_(AD)=vecF_(CD)=vecF_(CED)`
Hence net force on frame `= 3vecF_(CD)`
`=3i(vecixxvecb)=3xx1xx1xx4`
`F=12 N`


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