Constant temperature of ends are T_(1) and T_(2) (where T_(1)gtT_(2)) for a conducting rod of 'L' length and cross-sectional area A. What would be the rate of heat transfer in thermal steady state ?

Constant temperature of ends are T_(1) and T_(2) (where T_(1)gtT_(2))

1.	Constant temperature of ends are T_(1) and T_(2) (where T_(1)gtT_(2)) for a conducting rod of 'L' length and cross-sectional area A. What would be the rate of heat transfer in thermal steady state ?
Answer» `(dQ)/(dt)=(KA(T_(1)-T_(2)))/(L)` `(dQ)/(dt)=KAL(T_(1)-T_(2))` `(dQ)/(dt)=(KA(T_(1)-T_(2)))/(2)` `(dQ)/(dt)=(KL(T_(1)-T_(2)))/(A)` SOLUTION :KNOWLEDGE BASED question