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Constract the composition table/multiplication table for the binary operation * defined on {0,1,2,3,4}by a**b =axxb ("mod" =5). Find the identity element if any. Also find the inverse elements of 2 and 4. |
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Answer» SOLUTION :`A ={0,1,2,3,4}` `a**b =axx b "mod" 5` ![]() As 3rd row is identical to the FIRST row we have 1 is the IDENTITY CLEARLY `2^(-1) =3 "and" 4^(-1) =4.` |
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