InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
Construct a cell using given electrodes at `298K` and also calculate its standart `EMF`. Given ` :` `E^(c-)._(Zn|Zn^(2+))=0.76V` `E^(c-)._(Cu^(2+)|Cu)=0.34V` |
|
Answer» Note that `E^(c-)._(Zn|Zn^(2+))` is the standard oxidation potential valuse while that of `E^(c-)._(Cu^(2+)|Cu)` is standard reduction potential value. Therfore, `E^(c-).-(Zn^(2+)|Zn)(` standard reductio potential `)` value is `-0.76v`. Comparing the two standard reduction potential values. `:. E^(c-)._((Cu^(2+)|Cu))gtE^(c-)._((Zn^(2+)|Zn))` Hence, copper electrode will act as cathode and Zinc electrode will act as anode. The cell representation of the cell is `:` `Zn(s)|Zn^(2+)(1.0M)||Cu^(2+)(1.0M)|Cu(s)` `E^(c-)._(cell)=(E^(c-)._(reduction))_(cathode)-(E^(c-)._(reduction ))_(anode)` `=0.34-(-0.76)=1.1V` |
|