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Construct a triangle ABC with AB = 5.5 cm, AC = 6 cm and ∠BAC=105∘. Mark the point of intersection of the locus of points equidistant from BA and BC and the locus of points equidistant from B and C, as P. Then the length of PC is ___ cm. 4.8

Answer» Construct a triangle ABC with AB = 5.5 cm, AC = 6 cm and BAC=105. Mark the point of intersection of the locus of points equidistant from BA and BC and the locus of points equidistant from B and C, as P. Then the length of PC is ___ cm.
  1. 4.8


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