Construct a triangle ABCin which BC=7cm, angle B=75 and AB+AC=13cm

1.	Construct a triangle ABCin which BC=7cm, angle B=75 and AB+AC=13cm
Answer» Thc Given : Base BC = 7cm, angle B = 75° and sum of two sides AB + AC = 13\xa0cm.Required : To Construct ∆ABCSTEPS OF CONSTRUCTION :1. Draw a ray BX and cut off a line segment BC = 7cm; from it.2. At B; construct angle YBX = 75°3. With B as centre and radius = 13\xa0cm (because AB + AC = 13cm) draw an arc to meet BY at D.4. Join CD5. Draw Perpendicular bisector PQ of CD intersecting BD at A.6. Join ACThen ABC is the required triangle.A lies on perpendicular bisector of CD.Therefore, AC = AD=> AB = BD - AD=> AB = BD - AC=> AB + AC = BD = 13cm\xa0

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