1.

construct a triangle XYZ in which angle Y =30 degrees,angle Z=90 degrees and XY + YZ + ZX = 11 cm

Answer»

Steps of Construction:

1.Draw a line segment PQ = 11 cm.( = AB + BC + CA).

2.At P construct an angle of 30° and at Q, an angle of 90°.

3.Bisect these angles. Let the bisectors of these angles intersect at a point A.

4.Draw perpendicular bisectors DE of AP to intersect PQ at B and FG of AQ to intersect PQ at C.

5.Join AB and AC. Then, ABC is the required triangle.



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