Construct Δ DEF such that DE = 5 cm, DF = 3 cm and m∠ EDF = 90 .

1.	Construct Δ DEF such that DE = 5 cm, DF = 3 cm and m∠ EDF = 90 .
Answer» To construct: Δ DEF where DE = 5 cm, DF = 3 cm and m∠ EDF = 90 . Steps of construction: (a) Draw a line segment DF = 3 cm. (b) At point D, draw an angle of 90 with the help of compass i.e., ∠ XDF = 90 . (c) Taking D as centre, draw an arc of radius 5 cm, which cuts DX at the point E. (d) Join EF. It is the required right angled triangle DEF.

Answer»

To construct: Δ DEF where DE = 5 cm, DF = 3 cm and m∠ EDF = 90 .

Steps of construction:

(a) Draw a line segment DF = 3 cm.

(b) At point D, draw an angle of 90 with the help of compass i.e., ∠ XDF = 90 .

(d) Join EF.

It is the required right angled triangle DEF.

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Construct Δ DEF such that DE = 5 cm, DF = 3 cm and m∠ EDF = 90 .

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