InterviewSolution
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Convert (A + C)(B + \(\bar C\)) into canonical POS. |
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Answer» Y = (A + C)(B + \(\bar C\)) = (A + O + C)(O + B + \(\bar C\)) = (A + B\(\bar B\) + C)(A\(\bar A\) + B + \(\bar C\)) = (A + B + C)(A + \(\bar B\) + C)(A + B + \(\bar C\))(\(\bar A\) + B + \(\bar C\)) |
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