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Convert newton into dyne |
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Answer» Solution :Dimensional formula of force is `M^(1) L^(1) T^(-2)` IN = n dynes `rArr n= N`/dynes `therefore n_(2)= n_(1) [(M_(1))/(M_(2))]^(1) [(L_(1))/(L_(2))]^(1) [(T_(1))/(T_(2))]^(-2)` `rArr n= [(1kg)/(1g)] [(1M)/(1cm)]^(1) [(1S)/(1s)]^(-2) ((n_(2))/(n_(1))=n)` `rArr n= [(1000g)/(1g)] [(100cm)/(1cm)]^(1) [(1s)/(1s)]^(-2)` `rArr n= [1000] xx [100]^(1) xx [1]^(2) = 10^(7)` `therefore` 1 newton `= 10^(7)` dynes Alternate Method: `[F]= [MLT^(-2)]`, 1 newton =1 (kg) (m) `(s)^(-2)` `=1. (10^(3)g) (10^(2) CM) (s^(-2))= 10^(5) (g) (cm) (s)^(-2)` 1 newton `= 10^(5)` dynes |
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