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Convert the following expression into its canonical POS form :F(X, Y, Z) = (X + Y')·(Y' + Z) |
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Answer» F(X, Y, Z) = (X + Y')·(Y' + Z) = (X + Y' + ZZ') (XX' + Y' + Z) = (X + Y' + Z) (X + Y' + Z') (X + Y' + Z) (X' + Y' + Z) |
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