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Convert the following expression into its canonical POS form: F(X, Y, Z) = (X + Y) . (Y’ + Z) |
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Answer» F(X, Y, Z) = (X + Y’).(Y’ + Z) By De-Morgan’s theorem, we have ((X + Y’).(Y’ + Z))’ = (X + Y’)’ + (Y’+ Z)’ =X’.Y” + Y”.Z’ = X’.Y + Y.Z’ = Y.(X’ + Z’) Again applying De-Morgan’s theorem, we have (Y.(X’ + Z’))’ = (X’ + Z’)’ |
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