InterviewSolution
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Convert the general numbers into its vinkulum. (i) 8(ii) 27 (iii) 82 (iv) 78 (v) 96 |
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Answer» (i) 8 Hints : (a) Put vinkulum line on the parammitra digit of 8 i.e.,2 = bar 2 (b) Put one more sign on poorven digit of 8 i.e., 0 = bar \(\dot{0}\)2 (c) Write \(\dot{0}\) = 1. (d) Thus, we got the vinkulum of 8 = bar 2 (ii) 27 Hints : = bar 87 (a) Digit 7 would be as it is and \(\dot{0}\) 8 bar 7 = 7 vinkulum line would be on param = 187 mitra digit of 2 i.e., 8. (b) One more sign on the poorven of 8 i.e., 0. (c) Write \(\dot{0}\) = 1, (d) Thus, we got vinkulum of 27 (iii) 82 Hint : = 2 bar 2 (a) Digit 2 would be as it is and vinkulum line would be on = \(\dot{0}\) 2 bar 2 parammitra digit of 8 i.e., 2. = 1 2 bar 2 (b) One more sign on the poorven digit of 8 ie., 0. (c) Write \(\dot{0}\) = 1 (d) Thus, we get vinkulum of 82. (iv) 78 Hint : = 3 bar 8 (a) Digit 8 would be as it is and vinkulum line would be on = \(\dot{0}\) 3 bar 8 parammitra digit of 7 i.e., 3. = 1 3 bar 8 (b) One more sign on the poorven digit of 7 ie., 0 (c) Write \(\dot{0}\) = 1. (d) Thus, we got vinkulum of 78. (v) 96 Hint : = 1 bar 6 (a) Digit 6 would be as it is and = \(\dot{0}\) 1 bar 6 vinkulum line would be on parammitra digit of 9 i.e., 1. = 1 1 bar 6 (b) One more sign on the poorven digit of 9 Le., 0. (c) Write \(\dot{0}\) = 1. (d) Thus, we got vinkulum of 96 |
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