1.

Coordinates of the vertices B and C of the base of a triangle ABC are (-a,0) and (a, 0) respectively. If C-B=pi//3, the vertex A lies on the curve

Answer»

`X^(2)-y^(2)+2sqrt(3)xy-a^(2)=0`
`x^(2)+y^(2)+2sqrt(3)xy-a^(2)=0`
`sqrt(3)(x^(2)-y^(2))+2xy-sqrt(3)a^(2)=0`
`sqrt(3)(x^(2)+y^(2))-2xy+sqrt(3)a^(2)=0`

Answer :C


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