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Coordination number of Cr is six. A comlex ion of Cr with `C_(2)O_(4)^(2-)` end and superoxide ion, `O_(2)^(2-)` has the fomula , `[Cr(CO_(2)O_(4))_(x)(en)_(y)(O_(2))_(z)]^(-)` The ratio `x:y:z` will beA. `1:1:1`B. `1:1:2`C. `1:2:2`D. `2:1:1` |
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Answer» (b) The ratio x,y and z be such that, total chrage `=-1 3+1(1-2)+1xx0+2(-1)=-1` The ratio of `x:y:z=1:1:2` |
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