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Coordination number of `Ni` in `[Ni(C_2O_4)_3]^(4-)` is:A. 3B. 6C. 4D. 5 |
Answer» Correct Answer - B `C_(2)O_(4)^(2-)` is a bidentate group . As the complex contains three bidentate groups , the central metal ion has a co-ordination number of 6 |
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