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Coordination number of `Ni` in `[Ni(C_2O_4)_3]^(4-)` is:A. (a) `3`B. (b) `4`C. (c) `5`D. (d) `6` |
Answer» Correct Answer - D `C_2O_4^(2-)` is a bidentate group. As the complex contains three bidentate groups, the central metal ion has a coordination number of 6. |
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