1.

Coplete the following tablemass velocity kinetic energy50kg 2m/s ................. 4m/s 5J​

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Answer:

A 50 kg MASS is travelling at a speed of 2 m/s. Another 60kg mass is travelling at a speed of 12 m/s in the same direction, strikes the first mass. After the collision the 50kg mass is travelling with a speed of 4 m/s. The coefficient of restitution of the collision is :

Explanation:

Given,

m

1

=50kg

m

2

=60kg

V

1I

=2m/s

v

2i

=12m/s

v

1f

=4m/s

We know that there is no external force on the SYSTEM of two mass.

So here we can use momentum conservation for the collision.

m

1

v

1i

+m

2

v

2i

=m

1

v

1f

+m

2

v

2f

Now we have,

50(2)+60(2)=50(4)+60v

2f

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