Copper crystallises into a fee lattice. Its edge length is 3.62 xx 10^(-8) cm. Calculate the density of copper (atomic mass of Cu=63-5 u, N_A= 6-022 xx 10^(23) mol^(-1)).

Copper crystallises into a fee lattice. Its edge length is 3.62 xx 10^

1.	Copper crystallises into a fee lattice. Its edge length is 3.62 xx 10^(-8) cm. Calculate the density of copper (atomic mass of Cu=63-5 u, N_A= 6-022 xx 10^(23) mol^(-1)).
Answer» SOLUTION :For FCC, `r=a/(2sqrt2) or a=2sqrt2r=2xx1.414xx128` pm =362 pm `rho=(ZxxM)/(a^3xxN_0)=(4xx63.5 "g mol"^(-1))/((362xx10^(-10)cm)^3xx6.02xx10^23 mol^(-1))=8.9 "g cm"^(-3)` Alternatively, `rho="Mass of unit CELL "/"Volume of unit cell "=(4xx(63.5 "g mol"^(-1)//6.02xx10^23 mol^(-1)))/((362xx10^(-10)cm)^3)=8.9 g cm^(-3)`