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Copper crystallizes into a FCC lattice with edge length `3.61 xx 10^(-8)` cm . Show that the calculated density is in agreement with its measured value of `8.92 g. cm^(-3)` . |
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Answer» Density `d = (ZM)/(a^(3) xx N_(A))` Given edge length = `3.61 xx 10^(-8)` cm For FCC lattice of copper Z = 4 Atomic mass of copper M = 63.5 gms/mole `d = (4 xx 63.5)/((3.61 xx 10^(-8))^(3) xx 6.023 xx 10^(23))` `= 8.97 g//cm^(3)` The calculated value is approximately in agreement with the measured value `8.92 g// cm^(3)`. |
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