Copper dissolves in dilute nitric acis but not in dilute HCI Explain

1.	Copper dissolves in dilute nitric acis but not in dilute HCI Explain
Answer» Solution :Since `E^(@)` of `Cu^(2+)//Cu` electrode (+0.34 V) is higher than that of `H^(+)//H_(2)` electrode (0.0V) therefore `H^(+)` ions cannot oxidise Cu to `Cu^(2+)` ions and hence Cu does not dissolve in dil HCI in CONTRAST the electrode potential of `NO_(3)^(-)//NO` electrode (+0.97 V) is HIGER than that of COPPER electrode and hence it can oxidise Cu to `Cu^(2+)` ions and hence Cu dissolve in dil `HNO_(3)` thus cu dissolves in dil `HNO_(3)` DUE to oxidation of Cu by `NO_(3)^(-)` ions and not by `H^(+)` ions

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