1.

Copper (II) chloride reacts with lead to form a solution of lead chloride and Copper.​

Answer»

CORRECT Question:-

Convert the following TEXT equation to SYMBOLIC format. (Also, BALANCE it.)

Answer:-

Copper (II) = {Cu}^{2+}

Chloride = {Cl}^{-}

∴ Copper Chloride = CuCl_2

Lead (II) = {Pb}^{2+}

∴ Lead Chloride = PbCl_2

So, our equation (skeletal equation) WOULD be:-

\boxed{ CuCl_2 \ (s) + Pb \ (s) \longrightarrow PbCl_2 \ (l) + Cu \ (s) }

We can observe that, the equation follows law of conservation of mass, i.e. number of atoms before reaction and after reaction are same. Therefore, it is the balanced equation.


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