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Copper sulphate crystals contains `25.45 % Cu and 36.07 % H_(2)O`. If the law of constant composition is true, calculate the weight of copper required to obtained `40 g` of crystalline copper sulphate. |
Answer» The chemical formula of copper sulphite crystals is `CuSO_(4).5H_(2)O`. According to the data, Percentage of `Cu = 25.45 % ` , Percentage of `H_(2)O = 36.07 %` Percentage of `SO_(4) = 100-(25.45 +36.07) = 100-61.52 = 38.48 %` Since the law of constant composition is true, the percentage composition of the other sample of copper sulphite crystals must also remais the same Now, 100 g of copper sulphate crystals contain `Cu = 25.45 g` `:.` 50 g of copper crystals contain `Cu=((25.45g))/((100g))xx(40g)=10.18g`. |
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