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Correct set of four quantum numbers for the valence (outermost) electron of rubidium `(Z = 37)` isA. `5, 0, 0, + (1)/(2)`B. `5, 1, 0, +(1)/(2)`C. `5, 1, 1, +(1)/(2)`D. `6, 0, 0, +(1)/(2)` |
Answer» Correct Answer - A The electronic configuration rubidium (Z=37) is `[Kr]^(36)5s^(1)` For 5s electron , `n=5, l=0, m=0, s=+(1)/(2)` |
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